Composite Plate Bending Analysis With Matlab Code __top__
% Composite Plate Bending Analysis (FSDT) clear; clc; % 1. Material Properties (e.g., Carbon/Epoxy) E1 = 175e9; % Pa E2 = 7e9; % Pa G12 = 3.5e9; % Pa nu12 = 0.25; nu21 = nu12 * E2 / E1; % 2. Plate Geometry and Mesh a = 1.0; % Length (m) b = 1.0; % Width (m) h = 0.01; % Total Thickness (m) q0 = -10000; % Applied Load (N/m^2) % 3. Layup Sequence (Angles in degrees) layup = [0, 90, 90, 0]; n_layers = length(layup); t_layer = h / n_layers; z = -h/2 : t_layer : h/2; % Z-coordinates of layer interfaces % 4. Initialize ABD Matrices A = zeros(3,3); B = zeros(3,3); D = zeros(3,3); % Reduced Stiffness Matrix (Q) for orthotropic ply Q_bar = zeros(3,3); Q11 = E1 / (1 - nu12*nu21); Q12 = nu12 * E2 / (1 - nu12*nu21); Q22 = E2 / (1 - nu12*nu21); Q66 = G12; Q = [Q11, Q12, 0; Q12, Q22, 0; 0, 0, Q66]; % 5. Build ABD Matrix for i = 1:n_layers theta = deg2rad(layup(i)); T = [cos(theta)^2, sin(theta)^2, 2*sin(theta)*cos(theta); sin(theta)^2, cos(theta)^2, -2*sin(theta)*cos(theta); -sin(theta)*cos(theta), sin(theta)*cos(theta), cos(theta)^2-sin(theta)^2]; Q_layer = inv(T) * Q * (T'); % Transformed stiffness A = A + Q_layer * (z(i+1) - z(i)); B = B + 0.5 * Q_layer * (z(i+1)^2 - z(i)^2); D = D + (1/3) * Q_layer * (z(i+1)^3 - z(i)^3); end % 6. Navier Solution (Simplified for m=1, n=1) m = 1; n = 1; alpha = m * pi / a; beta = n * pi / b; % Bending Stiffness Component (D11 for a simple case) % For a symmetric cross-ply, w_max calculation: D11 = D(1,1); D12 = D(1,2); D22 = D(2,2); D66 = D(3,3); w_center = q0 / (pi^4 * (D11*(m/a)^4 + 2*(D12 + 2*D66)*(m/a)^2*(n/b)^2 + D22*(n/b)^4)); fprintf('Max Central Deflection: %.6f mm\n', w_center * 1000); Use code with caution. 4. Interpreting Results
Define elastic constants for a single lamina (E1, E2, ν12nu sub 12
), and the stacking sequence (layer angles and thicknesses). Calculate Reduced Stiffness ( For each layer, transform the orthotropic stiffness matrix
function T = transformation_matrix(deg) theta = deg * pi/180; m = cos(theta); n = sin(theta); T = [m^2, n^2, 2 m n; n^2, m^2, -2 m n; -m n, m n, m^2 - n^2]; end
% Full displacement vector U = zeros(nDof,1); U(freeDOF) = Uf; Composite Plate Bending Analysis With Matlab Code
for gp = 1:4 % bending/membrane integration (2x2) xi = gauss2(gp,1); eta = gauss2(gp,2); w = w2(gp);
%% Composite Plate Bending Analysis using CLPT and Navier Solution % This script calculates deflections, strains and stresses for a simply % supported rectangular composite laminate under transverse load. % The laminate is assumed specially orthotropic (D16 = D26 = 0). For general % laminates a different denominator is required (see Section 5). % % Author: [Your Name] % Date: [Current Date] % -------------------------------------------------------------------------
Standard isotropic plate theories don't work for composites because material properties change with direction (anisotropy) and layers (lamination). Classical Lamination Theory (CLT) simplifies a 3D laminate into a 2D surface by assuming: Kirchhoff’s Hypothesis:
D11𝜕4w𝜕x4+2(D12+2D66)𝜕4w𝜕x2𝜕y2+D22𝜕4w𝜕y4=q(x,y)cap D sub 11 partial to the fourth power w over partial x to the fourth power end-fraction plus 2 open paren cap D sub 12 plus 2 cap D sub 66 close paren the fraction with numerator partial to the fourth power w and denominator partial x squared partial y squared end-fraction plus cap D sub 22 partial to the fourth power w over partial y to the fourth power end-fraction equals q open paren x comma y close paren represents the transverse deflection. Navier’s Solution for Simply Supported Plates % Composite Plate Bending Analysis (FSDT) clear; clc; % 1
The transverse shear strains are: [ \gamma_xz = \frac\partial w\partial x + \theta_x, \quad \gamma_yz = \frac\partial w\partial y + \theta_y ]
Now produce final answer. Composite Plate Bending Analysis With Matlab Code: A Comprehensive Guide
% Summation over Fourier series for i = 1:length(x_plot) for j = 1:length(y_plot) x = X(i,j); y = Y(i,j); sum_w = 0; for m = 1:2:Mmax for n = 1:2:Nmax sum_w = sum_w + Wmn(m,n) * sin(m pi x/a) * sin(n pi y/b); end end w(i,j) = sum_w; end end
Ke = zeros(20,20); Nnodes = 4; ndof = 5; Layup Sequence (Angles in degrees) layup = [0,
% Fourier series terms Mmax = 51; % number of sine terms in x-direction (odd numbers only) Nmax = 51; % number of sine terms in y-direction
% Gauss quadrature (2x2 points) gauss_pts = [-1/sqrt(3), 1/sqrt(3)]; gauss_wts = [1, 1];
Different plate theories are used based on the thickness of the plate and the desired accuracy: