# Outer loop for Rows for i in range(ROWS):
If canvas is 400×400, each square = 50×50.
to create a checkerboard pattern in the top and bottom three rows, while leaving the middle two rows as
If you're also working on , let me know—the logic changes slightly to focus on a full-board pattern or different row offsets. 916 checkerboard v1 codehs fixed
To fix the CodeHS exercise, the key is not just printing the right visual output, but correctly modifying a list of lists using nested for loops and assignment statements . The Correct Logic
If the sum of the row and column is (i + j = even), you place a 1.
What your asks for (for example, if they want specific colors or variables changed) If you need help with the Karel versions of this assignment # Outer loop for Rows for i in
To fix the assignment, you must ensure you are not just printing the final output, but actually modifying the elements of a 2D list (grid) using assignment statements . The autograder specifically checks for code that sets elements to 1 . Fixed Python Code
For graphical checkerboards using CodeHS’s built-in graphics library, follow this correct implementation:
This causes the second row to start with 0 instead of 1 , creating vertical stripes instead of a checkerboard pattern. The Fixed Code Solution The Correct Logic If the sum of the
: Always use (row + col) % 2 == 0 pattern. Never rely solely on row or column index individually. If starting with a different color, adjust the condition accordingly.
Ensure you loop rows 0–7 and columns 0–7.
s) to only appear on the top and bottom sections. A common fix is to use a conditional statement like if row < 3 or row > 4: to only assign s in those specific row ranges. Step-by-Step Implementation Guide Initialize the Board: Create an 8x8 list of lists filled with zeros. my_grid = [[0] * 8 for i in range(8)] Nested Loop Assignment: Loop through every row and column. Use an
def create_board(): board = [] for i in range(8): row = [] for j in range(8): # Check if the sum of indices is even or odd if (i + j) % 2 == 0: row.append(0) else: row.append(1) board.append(row) return board # Usage my_board = create_board() print_board(my_board) Use code with caution. Copied to clipboard 💡 Key Logic: The Modulo Operator
var yPos = r * SQUARE_DIMENSION; : This ensures that as the row ( r ) increases, the square moves downward.
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